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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios Using Right Angled Triangle
A long string...
Question
A long string under tension of
100
N
has one end at
x
=
0
. A sinusoidal wave is generated at
x
=
0
whose equation is given by
y
=
(
0.01
c
m
)
sin
[
(
π
x
10
m
)
−
50
π
t
(
s
e
c
)
]
Draw velocity time graph of particle at
x
=
5
m
.
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Solution
y
=
0.01
c
m
s
i
n
(
π
x
10
−
50
π
t
)
d
y
d
t
=
(
−
50
π
)
(
0.01
)
c
o
s
(
π
x
10
−
50
π
t
)
a
t
x
=
5
m
V
=
(
−
50
π
)
(
0.01
)
s
i
n
(
50
π
t
)
=
−
A
s
i
n
(
50
π
t
)
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Similar questions
Q.
A long string under tension of
100
N
has one end at
x
=
0
. A sinusoidal wave is generated at
x
=
0
whose equation is given by
y
=
(
0.01
c
m
)
sin
[
(
π
x
10
m
)
−
50
π
t
(
s
e
c
)
]
Find the average power transmitted by the wave.
Q.
A long string under tension of
100
N
has one end at
x
=
0
. A sinusoidal wave is generated at
x
=
0
whose equation is given by
y
=
(
0.01
c
m
)
sin
[
(
π
x
10
m
)
−
50
π
t
(
s
e
c
)
]
Sketch the shape of the string at
t
=
1
50
s
e
c
.
Q.
A travelling wave is produced on a long horizontal string by vibrating an end up and down sinusoidally. The amplitude of vibration is 1⋅0 and the displacement becomes zero 200 times per second. The linear mass density of the string is 0⋅10 kg m
−1
and it is kept under a tension of 90 N. (a) Find the speed and the wavelength of the wave. (b) Assume that the wave moves in the positive x-direction and at t = 0, the end x = 0 is at its positive extreme position. Write the wave equation. (c) Find the velocity and acceleration of the particle at x = 50 cm at time t = 10 ms.
Q.
A sinusoidal wave travelling in the positive direction on stretched string has amplitude
20
c
m
, wavelength
1
m
and wave velocity
5
m
/
s
. At
x
=
0
and
t
=
0
, it is given that
y
=
0
and
d
y
d
t
<
0
. Find the wave function
y
(
x
,
t
)
.
Q.
A sinusoidal progressive wave is generated in a string. It's equation is given by
y
=
(
2
m
m
)
sin
(
2
π
x
−
100
π
t
+
π
/
3
)
.
The time when particle at
x
=
4
m
first passes through mean position, will be
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