A long string with a charge of λ per unit length passes through an imaginary cube of edge length a. The maximum flux of the electric field through the cube will be:
A
λa/ϵ0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√2λa/ϵ0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6λa2/ϵ0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
√3λa/ϵ0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D√3λa/ϵ0 The maximum flux will pass through the cube if the charge enclosed is the maximum (from Gauss' Law). Thus, for enclosing maximum charge, the string should lie along the diagonal of length, √3a Total charge, enclosed will √3aλ So, the flux passing through the cube is, ϕ=√3λaϵ0