A long thin magnet of moment M is bent into a semi circle. The decrease in the Magnetic moment is :

2 M / π

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π M / 2

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M (π - 2) / π

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M (2 - π) / 2

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Solution

The correct option is B $M (π - 2) / π$
$M a g n e t i c M o m e n t = M a g n e t i c L e n g t h \times P o l e S t r e n g t h$
$L_{n e w} = 2 L / \prod$
$∴ M_{n e w} = 2 M / \prod$
$∴ c h a n g e = M - 2 M / \prod$

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