A long, vertical wire carrying a current of 10 A in the upward direction is placed in a region where a horizontal magnetic field of magnitude $2.0 \times 10^{- 3} T$ exits from south to north. Find the point where the resultant magnetic field is zero.

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Solution

Given B= $2.0 \times 10^{- 3} T$

(from south to north)

A magnetic field will be north to south when required point will place west to wire. Then from question,

$2.0 \times 10^{- 3} = \frac{μ_{0} i}{2 π r}$

$\Rightarrow 2.0 \times 10^{- 3} = \frac{2 \times 10^{- 7} \times 10}{r}$

$\Rightarrow r = 10^{- 3} m = 1 m m$

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A long, vertical wire carrying a current of 10 A in the upward direction is placed in a region where a horizontal magnetic field of magnitude 2.0×10−3 T exits from south to north. Find the point where the resultant magnetic field is zero.

Given B=2.0×10−3 T (from south to north) A magnetic field will be north to south when required point will place west to wire. Then from question, 2.0×10−3=μ0i2πr ⇒2.0×10−3=2×10−7×10r ⇒r=10−3 m=1mm

A long, vertical wire carrying a current of 10 A in the upward direction is placed in a region where a horizontal magnetic field of magnitude $2.0 \times 10^{- 3} T$ exits from south to north. Find the point where the resultant magnetic field is zero.