Question

A loop $ABCDEFA$ of straight edges has six corner points A(0,0,0), B(5,0,0), C(5,5,0), D(0,5,0), E(0,5,5), F(0,0,5). The magnetic field in this region is $\overrightarrow{B}$ = $(3\hat{i}+4\hat{k})T$. The quantity of flux through the loop $ABCDEFA$ (in $Wb$) is

Answer 1

As we know, magnetic flux $=\overrightarrow{B}\cdot \overrightarrow{A}$
$$\begin{array}{cc}& ⟹(B_x+B_z)\cdot (A_x+A_z)\\ & ⟹(3\hat{i}+4\hat{k})\cdot (25\hat{i}+25\hat{k})\\ & ⟹(75+100)Wb\\ & ⟹175Wb\end{array}$$