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Question

A loop of a string of mass per unit length μ and radius R is rotated about an angle passing through centre perpendicular to the plane with n angular velocity ω. A small disturbance is created in the loop having the same sense of rotation. The liner speed of the disturbance for a stationary observer is

A
ωR
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B
2ωR
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C
3ωR
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D
zero
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Solution

The correct option is B 2ωR
2Tsindθ2=dmω2R

2T(dθ2)=λRdθω2R

Tλ=ω2R2

Therefore,

Tλ=ωR

Tλ=Vpulse&string=VpulseVstringωR=VPVS

Then,

VP=ωR+VS=ωR+ωR=2ωR

1482481_1295475_ans_875487860d284e53bffb430906c928c8.png

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