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Byju's Answer
Standard XII
Mathematics
Simple and Compound Event
A lot of 20...
Question
A lot of
20
bulbs contain
4
defective ones.Suppose the bulb drawn in
(
i
)
is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective ?
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Solution
Total numbers of bulbs
=
20
One non defective bulb is drawn in
(
i
)
then the total numbers of bulb left is
19
Total numbers of events
=
19
Favourable numbers of events
=
19
−
4
=
15
Probability that the bulb is not defective
=
15
19
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Similar questions
Q.
A lot of
20
bulbs contain
4
defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective? Suppose the bulb drawn in is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective ?
Q.
A lot of 20 bulbs contain 4 defective ones. One bulb is selected at random from the lot. What is the probability that this bulb is defective? Suppose the bulb selected in the previous case is not defective and is not replaced. Now one bulb is selected at random from the rest. What is the probability that this bulb is not defective?
Q.
Question 17 (ii)
(ii) Suppose the bulb drawn in (i) is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?
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