A lot of 20 bulbs contains 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

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Solution

Total number of outcomes = 20
Number of favourable outcomes = 4
Hence P (getting a defective bulb)
$= \frac{4}{20} = \frac{1}{5}$

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Similar questions

Q. A lot of

20

bulbs contains

4

defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

(i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this blb is defective?
(ii) Suppose the bulb drawn in (i) is not defective and not replaced Now, bulb is drawn at random from the rest. What is the probability that this bulb is not defective?

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A lot of 20 bulbs contains 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

Total number of outcomes = 20 Number of favourable outcomes = 4 Hence P (getting a defective bulb) =420=15

Total number of outcomes = 20
Number of favourable outcomes = 4
Hence P (getting a defective bulb)
$= \frac{4}{20} = \frac{1}{5}$