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Byju's Answer
Standard XII
Chemistry
Real Gases
A low pressur...
Question
A low pressures, the van der Waals equation is written as:
(
P
+
a
V
2
)
V
=
R
T
The compressibility factor is then equal to:
A
(
1
−
a
R
T
V
)
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B
(
1
−
R
T
V
a
)
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C
(
1
+
a
R
T
V
)
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D
(
1
+
R
T
V
a
)
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Solution
The correct option is
A
(
1
−
a
R
T
V
)
(
P
+
a
V
2
)
V
=
R
T
P
V
+
a
V
=
R
T
;
P
V
R
T
+
a
R
T
V
=
1
P
V
R
T
=
Z
(compressibility factor)
Z
=
1
−
a
R
T
V
Suggest Corrections
0
Similar questions
Q.
At low pressures, the van der waals equation is written as
[
p
+
a
v
2
]
V
=
R
T
.
The compressibility factor is then equal to
Q.
At low pressures (For 1 mole), the van der Waals equation is written as
[
p
+
a
V
2
]
V
=
R
T
The compressibility factor is then equal to:
Q.
Assertion :At low pressure van der Waal's equation is reduced to
[
P
+
a
V
2
]
V
=
R
T
. Reason: The compressibility factor corresponding to low pressure is given by:
1
−
R
T
V
a
.
Q.
The compressibility factors for 1 mole of real gases at low pressure, high pressure and that of gases of very low molar masses are
Z
1
,
Z
2
and
Z
3
. These are
Q.
Assertion :Compressibility factor Z according to van der Waal's equation may be written as
Z
=
1
1
−
(
n
b
V
)
−
a
n
R
T
V
. Reason: For real gases
Z
>
<
1
.
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