A machine depreciates at the rate of 10% of its value at the beginning of a year. If the present value of a machine is Rs. 4000, find its value after 3 years.
A
Rs. 1916
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B
Rs. 2916
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C
Rs. 3916
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D
Rs. 4916
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Solution
The correct option is BRs. 2916 Given:-
P=Rs. 4000
r=10%
n=3 years
Now, as the value of the machine depriciates every year by 10%,
A=P(1−r100)n=4000(1−10100)3=4000(0.9)3=Rs. 2916
Hence, the value of the machine after 3 years is Rs. 2916.