Question

A machine does a work of $25kJ$ in $3minutes$ and $20seconds$. Calculate the power of the machine in $kW$.

Answer 1

Step 1: Given data:

1. Work done$=$$25kJ=25000J$
2. Time taken$=3minand20s=200s$

Step 2: Calculating power by applying formula:

$Power\left(P\right)=\frac{Workdone\left(W\right)}{Timetaken\left(t\right)}$

$\Rightarrow P=\frac{25000J}{200s}=125W=0.125kW$

Hence, the power of the machine in $kW$ is $0.125kW$.