A machine gum fires a bulled of mass $50 g m$ with velocity $1000 m / s$ . If average force acting on tun is $200 N$ then find ou the maximum number of bullets fired per minute.

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Solution

Mass of each bullet $= 50 g = 0.05 k g$
Velocity $= 1000 m / s$
Let the number of bullets per sec $= n$
Average force acting on gun $= 200 N$
Rate of change of momentum=Force
$n m v = a v e r a g e f o r c e$
$n \times 0.05 \times 1000 = 200$
$50 n = 200$
$n = 4$
Number of bullets per second $= 4$
Number of bullets per minute $= 4 \times 60 = 240$
Thus, 240 bullets fired per minute.

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A machine gum fires a bulled of mass 50gm with velocity 1000m/s. If average force acting on tun is 200N then find ou the maximum number of bullets fired per minute.

Mass of each bullet=50g=0.05kgVelocity=1000m/sLet the number of bullets per sec =nAverage force acting on gun=200NRate of change of momentum=Forcenmv=averageforcen×0.05×1000=20050n=200n=4Number of bullets per second=4Number of bullets per minute=4×60=240Thus, 240 bullets fired per minute.

A machine gum fires a bulled of mass $50 g m$ with velocity $1000 m / s$ . If average force acting on tun is $200 N$ then find ou the maximum number of bullets fired per minute.