A machine gun fires 200 bullets per minute with a velocity of 60 m/s. What is the power of the machine gun if the mass of each bullet is 0.05g?

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Solution

We know that, kinetic energy = $\frac{1}{2} m v^{2}$
So total energy imparted to 200 bullets, $E = \frac{1}{2} \times 200 \times (\frac{0.05}{1000}) \times 60 \times 60 = 18 J$
So, power = $\frac{E n e r g y}{T i m e} = \frac{18}{60} J / s = 0.3 W$

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