A machine gun fires a bullet of mass $40 g$ with a velocity $1200 m/s$ . The man holding it can exert a maximum force of $144 N$ on the gun. How many bullets can be fired per second at most?

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Solution

The correct option is C $3$
We know that, force,

$F = \frac{Δ p}{Δ t} = \frac{n m v - 0}{t - 0}$

$\Rightarrow F = m v \times \frac{n}{t}$

$\Rightarrow 144 = 40 \times 10^{- 3} \times 1200 \times \frac{n}{t}$

$\Rightarrow \frac{n}{t} = 3$

Hence, option $(C)$ is the correct answer.

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Similar questions

Q. A machine gun fires a bullet of mass

40 g

with a velocity

1200 m s^{- 1}

. The man holding it can exert a maximum force of

144 N

on the gun. How many bullets can the man fire per second at the most?

A machine gun fires A bullet of mass 40 gram with the velocity of 1200m/s. The gun can exert a maximum force of 144N on the bullet. How many bullets can it fire per second at the most?

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A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fired per second at most?

The correct option is C 3We know that, force, F=ΔpΔt=nmv−0t−0 ⇒F=mv×nt ⇒144=40×10−3×1200×nt ⇒nt=3 Hence, option (C) is the correct answer.

A machine gun fires a bullet of mass $40 g$ with a velocity $1200 m/s$ . The man holding it can exert a maximum force of $144 N$ on the gun. How many bullets can be fired per second at most?

The correct option is C $3$
We know that, force,

$F = \frac{Δ p}{Δ t} = \frac{n m v - 0}{t - 0}$

$\Rightarrow F = m v \times \frac{n}{t}$

$\Rightarrow 144 = 40 \times 10^{- 3} \times 1200 \times \frac{n}{t}$

$\Rightarrow \frac{n}{t} = 3$

Hence, option $(C)$ is the correct answer.