A machine gun fires n bullets per second and the mass of each bullet is m .If speed of bullets is v, then force exerted on the machine gun will be

m n g

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m n v

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m n v g

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\frac{m n v}{g}

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Solution

The correct option is B $m n v$
Force is change in momentum.
$M o m e n t u m = m * v$
for one bullet $F o r c e = \frac{d (m o m e n t u m)}{d t i m e} = \frac{d (m * v)}{d t}$
for n bullets $F o r c e = \frac{d (m * v)}{d t} = n m v$

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A machine gun fires n bullets per second and the mass of each bullet is m .If speed of bullets is v, then force exerted on the machine gun will be

The correct option is B mnvForce is change in momentum.Momentum=m∗v for one bullet Force=d(momentum)dtime=d(m∗v)dtfor n bullets Force=d(m∗v)dt=nmv

The correct option is B $m n v$
Force is change in momentum.
$M o m e n t u m = m * v$
for one bullet $F o r c e = \frac{d (m o m e n t u m)}{d t i m e} = \frac{d (m * v)}{d t}$
for n bullets $F o r c e = \frac{d (m * v)}{d t} = n m v$