A machine gun has a mass of $20 k g$ . It fires $35 g$ bullet at the rate of $40$ bullet per second with a speed of $4 m / s .$ What force must the applied to the gun to keep it in position.

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Solution

$\frac{change in momentum}{t i m e} = F o r c e$
$m o m e n t u m = m v$
$F o r c e = \frac{n \times m \times v}{t} = \frac{40 \times 0.035 \times 4}{1} = 5.6 N$

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A machine gun has a mass of 20kg. It fires 35g bullet at the rate of 40 bullet per second with a speed of 4m/s. What force must the applied to the gun to keep it in position.

change in momentumtime=Forcemomentum=mvForce=n×m×vt=40×0.035×41=5.6N

A machine gun has a mass of $20 k g$ . It fires $35 g$ bullet at the rate of $40$ bullet per second with a speed of $4 m / s .$ What force must the applied to the gun to keep it in position.

$\frac{change in momentum}{t i m e} = F o r c e$
$m o m e n t u m = m v$
$F o r c e = \frac{n \times m \times v}{t} = \frac{40 \times 0.035 \times 4}{1} = 5.6 N$