A machine is used to displace a load of $200$ N through $5$ cm by an effort of $10$ N. If efficiency of the machine is $50 %$ . Find its mechanical equivalent.

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Solution

The correct option is A 20
Load = $w = 200 N$
Distance moved by the load = $5 c m = .05 m$
$E f f o r t (P) = 10 N$
$n (E f f i c i e n c y) = 50 %$
$M A = L o a d / E f f o r t = W / P = 200 N / 10 N = 20$

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A machine is used to displace a load of 200 N through 5 cm by an effort of 10 N. If efficiency of the machine is 50%. Find its mechanical equivalent.

The correct option is A 20Load = w=200NDistance moved by the load = 5cm=.05mEffort(P)=10Nn(Efficiency)=50%MA=Load/Effort=W/P=200N/10N=20

A machine is used to displace a load of $200$ N through $5$ cm by an effort of $10$ N. If efficiency of the machine is $50 %$ . Find its mechanical equivalent.

The correct option is A 20
Load = $w = 200 N$
Distance moved by the load = $5 c m = .05 m$
$E f f o r t (P) = 10 N$
$n (E f f i c i e n c y) = 50 %$
$M A = L o a d / E f f o r t = W / P = 200 N / 10 N = 20$