A machine requires an effort of $15 k g f$ for a load of $40 k g f$ . Find its mechanical advantage.

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Solution

Given: Load = $40 k g f$ and effort = $15 k g f$ .

We know, Mechanical advantage, $M A = \frac{L o a d}{E f f o r t}$

$∴ M A = \frac{40}{15} = 2.7$

Since, MA is a ratio of two same quantities, it does not have a unit. It is just a constant for the given system.

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