Question

A magazine charges $₹300$ per $10$ sq cm area for advertisement. A company decided to order a half page advertisement. If each page of the magazine is $15\text{cm}\times 24\text{cm}$, what amount will the company has to pay for it?

Answer 1

• The area $A$ of the rectangle with length $l$ and width $w$ is given by, $A=l\times w$.

Step 1: Substitute $l=15$, $w=24$ into the formula $A=l\times w$ and find the area of the page.

$\begin{array}{rcl}A& =& 15\times 24\\ & =& 360{\text{cm}}^2\end{array}$

Step 2: The company has decided to order a half-page advertisement, so find the area of half of the page.

$\frac{360}{2}=180{\text{cm}}^2$

Step 3: Find the charges for advertising per sq cm.

$\frac{300}{10}=₹30/{\text{cm}}^2$

Step 4: Find the charges for advertising the area of $180{\text{cm}}^2$.

$180\times 30=₹5400$

Hence, the amount of $₹5400$ the company has to pay for advertisement.