A maglev train travels at $200 k m h^{- 1}$ . What will be the distance covered by it at the end of $2.5 h$ ?

400 k m

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500 k m

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600 k m

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300 k m

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Solution

The correct option is B $500 k m$
Given:
Speed of the train, $v = 200 k m h^{- 1}$
Time taken by the train, $t = 2.5 h o u r s$

Distance uis given by the produc tof speed and time. Hence, distance covered is:
$d = v t$
$d = 200 k m h^{- 1} \times 2.5 h$ = $500 k m$

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