A magnet has a pole strength of 1000 milli amp.m. The magnetic field intensity at a distance of 10 cm from its North pole is

\frac{25}{π} A / m

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\frac{π}{25} A / m

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\frac{100}{π} A / m

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\frac{π}{100} A / m

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Solution

The correct option is A $\frac{25}{π} A / m$
Magnetic field intensity $= \frac{p}{4 π d^{2}}$
$= \frac{1000 \times 10^{- 3}}{4 π (10 \times 10^{- 2})^{2}}$
$= \frac{25}{π} A / m$

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A magnet has a pole strength of 1000 milli amp.m. The magnetic field intensity at a distance of 10 cm from its North pole is

The correct option is A 25πA/mMagnetic field intensity=p4πd2=1000×10−34π(10×10−2)2=25πA/m

The correct option is A $\frac{25}{π} A / m$
Magnetic field intensity $= \frac{p}{4 π d^{2}}$
$= \frac{1000 \times 10^{- 3}}{4 π (10 \times 10^{- 2})^{2}}$
$= \frac{25}{π} A / m$