A magnet is suspended horizontally in the earth’s magnetic field. When slightly displaced, it oscillates in the horizontal plane with a period T. If a piece of wood having the same moment of inertia as the magnet is attached to the magnet, the new period of oscillation is

$\frac{T}{\sqrt{2}}$

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$\frac{T}{2}$

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$\sqrt{2} T$

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$2 T$

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Solution

The correct option is C
$\sqrt{2} T$

$T = 2 π \sqrt{\frac{I}{m B_{H}}}; T^{^{'}} = 2 π \sqrt{\frac{2 I}{m B_{H}}} = \sqrt{2} T$

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A magnet is suspended horizontally in the earth’s magnetic field. When slightly displaced, it oscillates in the horizontal plane with a period T. If a piece of wood having the same moment of inertia as the magnet is attached to the magnet, the new period of oscillation is

The correct option is C √2T T=2π√ImBH; T′=2π√2ImBH=√2T

The correct option is C
$\sqrt{2} T$

$T = 2 π \sqrt{\frac{I}{m B_{H}}}; T^{^{'}} = 2 π \sqrt{\frac{2 I}{m B_{H}}} = \sqrt{2} T$