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Standard XII

Physics

Magnetic Moment

A magnet of l...

Question

A magnet of length $0.1 m$ has a pole strength of $4 A m$ . If it is making an angle $45^{o}$ with the direction of uniform magnetic field of $4 W b / m^{2}$ , the torque experienced by it is :

1.13 N m

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1.6 N m

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0.8 N m

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1.32 N m

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Solution

The correct option is A $1.13 N m$
$θ = 45$ , $l = 0.1 m$ , $P = 4 A m$ , $θ = 45$ , $B = 4 T$ , $m = l p$
$τ = m \times B$
$= m B sin 45^{o}$
$τ = \frac{l p}{\sqrt{2}}$
$= \frac{0.1 \times 4 \times 4}{\sqrt{2}}$
$= 1.13 N m$

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A magnet of length 0.1m has a pole strength of 4Am. If it is making an angle 45o with the direction of uniform magnetic field of 4Wb/m2, the torque experienced by it is :

The correct option is A 1.13Nmθ=45, l=0.1m, P=4Am, θ=45, B=4T, m=lpτ=m×B=mBsin45oτ=lp√2=0.1×4×4√2=1.13Nm

A magnet of length $0.1 m$ has a pole strength of $4 A m$ . If it is making an angle $45^{o}$ with the direction of uniform magnetic field of $4 W b / m^{2}$ , the torque experienced by it is :

The correct option is A $1.13 N m$
$θ = 45$ , $l = 0.1 m$ , $P = 4 A m$ , $θ = 45$ , $B = 4 T$ , $m = l p$
$τ = m \times B$
$= m B sin 45^{o}$
$τ = \frac{l p}{\sqrt{2}}$
$= \frac{0.1 \times 4 \times 4}{\sqrt{2}}$
$= 1.13 N m$