A magnet of length 12 cm has pole strength 10 units. The magnet is placed at an angle $30^{\circ}$ with the direction of a uniform field of strength 0.5 oersted. The torque acting on the magnet is

30 dyne-cm

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20 dyne-cm

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40 dyne-cm

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36 dyne-cm

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Solution

The correct option is A 30 dyne-cm
Torque $(τ) = M B s i n θ$
$= (2 l m) B s i n θ$
$10 \times 12 \times 0.5 \times s i n 30^{\circ}$
$= \frac{60}{2} = 30$ dyne-cm

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A magnet of length 12 cm has pole strength 10 units. The magnet is placed at an angle 30∘ with the direction of a uniform field of strength 0.5 oersted. The torque acting on the magnet is

The correct option is A 30 dyne-cmTorque (τ)=MB sinθ =(2lm)Bsinθ 10×12×0.5×sin30∘ =602=30 dyne-cm

A magnet of length 12 cm has pole strength 10 units. The magnet is placed at an angle $30^{\circ}$ with the direction of a uniform field of strength 0.5 oersted. The torque acting on the magnet is

The correct option is A 30 dyne-cm
Torque $(τ) = M B s i n θ$
$= (2 l m) B s i n θ$
$10 \times 12 \times 0.5 \times s i n 30^{\circ}$
$= \frac{60}{2} = 30$ dyne-cm