A magnet of magnetic moment $20 C G S$ units is freely suspended in a uniform magnetic field of intensity $0.3 C G S$ units. The moment of work done in deflecting it by an angle of $30^{\circ}$ in $C G S$ units is

6

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3 \sqrt{3}

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3 (2 - \sqrt{3})

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3

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Solution

The correct option is B $3 (2 - \sqrt{3})$
Work done, $W = M B (1 - cos θ)$
$= 20 \times 0.3 (1 - cos 30^{\circ})$
$= 6 \times (1 - \frac{\sqrt{3}}{2}) = 3 (2 - \sqrt{3})$ .

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A magnet of magnetic moment 20 CGS units is freely suspended in a uniform magnetic field of intensity 0.3 CGS units. The moment of work done in deflecting it by an angle of 30∘ in CGS units is

The correct option is B 3(2−√3)Work done, W=MB(1−cosθ)=20×0.3(1−cos30∘)=6×(1−√32)=3(2−√3).

A magnet of magnetic moment $20 C G S$ units is freely suspended in a uniform magnetic field of intensity $0.3 C G S$ units. The moment of work done in deflecting it by an angle of $30^{\circ}$ in $C G S$ units is

The correct option is B $3 (2 - \sqrt{3})$
Work done, $W = M B (1 - cos θ)$
$= 20 \times 0.3 (1 - cos 30^{\circ})$
$= 6 \times (1 - \frac{\sqrt{3}}{2}) = 3 (2 - \sqrt{3})$ .