1
Question
A magnet of moment 4 Am2 is suspended in a uniform magnetic field of induction 5×10−4 T with its axis at right angles. When the magnet is released from it's position, the kinetic energy that it gains in passing to the stable equilibrium position is :
A magnet of moment 4 Am2 is suspended in a uniform magnetic field of induction 5×10−4 T with its axis at right angles. When the magnet is released from it's position, the kinetic energy that it gains in passing to the stable equilibrium position is :
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Solution
The correct option is B 2×10−3J
magnetic moment m=4 Am2
magnetic field B=5×10−4T
Potential energy of dipole placed in uniform field μ=−m.B...(i)
From energy conservation principle:
ΔK+ΔU=0...(ii)
K2−K1=(U1−U2)
K1=0, U1=0
U2=−mB from equation (i)
=−4×5×10−4
From equation (ii)
K2−0=0+20×10−4
K2=2×10−3 J
magnetic moment m=4 Am2
magnetic field B=5×10−4T
Potential energy of dipole placed in uniform field μ=−m.B...(i)
From energy conservation principle:
U2=−mB from equation (i)
=−4×5×10−4
ΔK+ΔU=0...(ii)
K2−K1=(U1−U2)
K1=0, U1=0
K2−K1=(U1−U2)
K1=0, U1=0
U2=−mB from equation (i)
=−4×5×10−4
From equation (ii)
K2−0=0+20×10−4
K2=2×10−3 J
K2−0=0+20×10−4
K2=2×10−3 J
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