A magnetic field B=2t+4t2 (where t= time) is applied perpendicular to the plane of a circular wire of radius r and resistance R. If all the units are in SI, the electric charge that flows through the circular wire during t=0s to t=2s is:
A
6πr2R
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B
20πr2R
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C
32πr2R
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D
48πr2R
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Solution
The correct option is B20πr2R Given B=2t+4t2 at t=0,B1=0 and at t=2,B2=2×2+4(2)2 =4+16=20Wb/m2 We have ΔQ=ΔϕR=πr2(B2−B1)R =πr2(20−0)R=20πr2R