Given, Magnetic field strength,
B=100 G=100×10−4 T
maximum number of turns per unit length,
nmax=1000 turns/m
Current carrying capacity of the coil
Imax=15A
Area of cross-section A≈10−3m2
Permeability of free space,
μ0=4π×10−7TmA−1
Magnetic field is given as
B=μ0NIl=μ0nI
⇒nI=Bμ0=100×10−44π×10−7
nI=7961
Then for nmax=1000 turns/m
I=79611000=7.961A
Therefore, 7.961A should be the current parameter to produce magnetic field of 100 G keeping number of turns per unit length as 1000 turns/m.
The current can be increase upto 15 A by decreasing the number of turns per unit length. Hence the parameters are not unique ans some adjustments within limits is possible.
Final Answer: 7.961A should be the current parameter to produce magnetic field of 100G keeping number of turns per unit length as 1000 turns/m.
The parameters are not unique and some adjustments within limits is possible.