A magnetic field of B=5t2 exists in a cylindrical region as shown in figure. A conducting square loop of side l=2cm is placed inside a cylinder such that one of the vertex of square is at the center of cylinder.
A
EMF induced in side AB at t = 2 sec is 4 mV
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B
Potential difference developed in side OA at t = 2 sec is 2 mV
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C
Potential difference across side AB at t = 2 sec is 2 mV
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D
EMF induced across side OA at t = 2 sec is 2mV
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Solution
The correct option is B Potential difference developed in side OA at t = 2 sec is 2 mV ε=dϕdt=ddt5t2×4×10−4=4tmV [EMF of loop] εOA=εOC=0 & εAB=εBC=ε2 εAB=4mv at t = 2