The correct option is A 50V
Answer is A.
In this case, B = 10 T, N = 50 turns, A = 100cm2=10−2m2 and dt = 0.1 second.
We know that, ϕ1=NBAcosθ=NBA(ascosθ=cos0=1).
Therefore, ϕ1=50×10×10−2=5weber.
When the coil is removed from the magnetic field, B = 0.
So, ϕ2=0.
Therefore, (ϕ2−ϕ2)=dϕ=(0−5)=−5weber.
We also know that e = −dϕdt=−50.1=50V.
Hence, the emf induced if the coil is removed from the magnetic field in 0.1 second is 50 V.