A magnetic flux of 5 microweber is linked with a coil when a current of 1 mA flows through it. Calculate self-inductance of the coil.

5 mA

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10 mH

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15 mH

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20 mH

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Solution

The correct option is A 5 mA
The correct answer is A
Magnetic flux $B = 5 m w = 5 \times 10^{- 6} m w$

$c u r r e n t I = 1 m A = 10^{- 3} A$

$s e l f - i n d u c t a n c e L = \frac{Q}{I}$

$L = \frac{5 \times 10^{6}}{10^{- 3}}$

$L = 5 \times 10^{- 3}$ Hen.

$L = 5 m h$

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A magnetic flux of 5 microweber is linked with a coil when a current of 1 mA flows through it. Calculate self-inductance of the coil.

The correct option is A 5 mAThe correct answer is AMagnetic flux B=5mw=5×10−6mwcurrentI=1mA=10−3Aself−inductanceL=QIL=5×10610−3L=5×10−3 Hen.L=5mh

The correct option is A 5 mA
The correct answer is A
Magnetic flux $B = 5 m w = 5 \times 10^{- 6} m w$

$c u r r e n t I = 1 m A = 10^{- 3} A$

$s e l f - i n d u c t a n c e L = \frac{Q}{I}$

$L = \frac{5 \times 10^{6}}{10^{- 3}}$

$L = 5 \times 10^{- 3}$ Hen.

$L = 5 m h$