A magnetic flux of $5 μ Wb$ is linked with a coil when a current of $1 mA$ flows through it. Find the self inductance of the coil?

2 mH

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3 mH

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4 mH

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5 mH

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Solution

The correct option is D $5 mH$
We know that
$ϕ = L I \Rightarrow L = \frac{ϕ}{I} = \frac{5 \times 10^{- 6}}{1 \times 10^{- 3}}$
$= 5 \times 10^{- 3} H = 5 mH$

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A magnetic flux of 5 μWb is linked with a coil when a current of 1 mA flows through it. Find the self inductance of the coil?

The correct option is D 5 mH We know that ϕ=LI⇒L=ϕI=5×10−61×10−3 =5×10−3 H=5 mH

A magnetic flux of $5 μ Wb$ is linked with a coil when a current of $1 mA$ flows through it. Find the self inductance of the coil?

The correct option is D $5 mH$
We know that
$ϕ = L I \Rightarrow L = \frac{ϕ}{I} = \frac{5 \times 10^{- 6}}{1 \times 10^{- 3}}$
$= 5 \times 10^{- 3} H = 5 mH$