A magnetic moment of 1.73BM will be shown by one among of the following compounds:
A
[Cu(NH3)4]2+
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B
[Ni(CN)4]2−
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C
TiCl4
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D
[CoCl6]−3
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Solution
The correct option is A[Cu(NH3)4]2+ Option (A) is correct. A magnetic moment of 1.73BM will be shown by [Cu(NH3)4]2+ as it is in d9 orbitals and contains 1 unpaired electron.