A magnetic pole of pole strength 9.2 A m. is placed in a field of induction 50x10 $^{- 6}$ Tesla. The force experienced by the pole is :

46N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\times

^{- 4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.6

\times

^{- 4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

460N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 4.6 $\times$ 10 $^{- 4}$ N
$m = 9.2 A m$
$B = 50 \times 10^{- 6} T$
$F = B \times m$
$F = 9.2 \times 50 \times 10^{- 6}$
$= 4.6 \times 10^{- 4} N$

Suggest Corrections

Similar questions

The force acting on a pole of strength of 20 Am is 8x10 $^{- 4}$ N, when placed in a magnetic field. The magnetic induction field strength is :

A magnet of magnetic moment $1.525 \times 10^{- 3} A . m^{2}$ . is placed in a magnetic field of induction field strength $0.1 g a u s s$ , perpendicular to the field direction. Then each pole experiences a force of $0.305 d y n e s$ . The distance between the two poles of the magnet is

A bar magnet of length 0.2 m and pole strength 5 A.m. should be kept in a uniform magnetic field of induction 15 tesla at angle ..... radians to the field so that the torque experienced by it will be 7.5N-m

Two north poles each of pole strength m and a south pole of pole strength m are placed at the three corners of an equilateral triangle of side a. The intensity of magnetic induction field strength at the centroid of the triangle is :

When a bar magnet of magnetic moment $¯ ¯¯¯¯ ¯ M$ is placed in a magnetic field of induction field strength $¯ ¯¯ ¯ B$ , each pole experiences a force of $¯ ¯¯ ¯ F$ then the distance between the South and North pole of the magnet measured inside it is :

Join BYJU'S Learning Program

A magnetic pole of pole strength 9.2 A m. is placed in a field of induction 50x10−6 Tesla. The force experienced by the pole is :

The correct option is C 4.6×10−4Nm=9.2AmB=50×10−6TF=B×mF=9.2×50×10−6 =4.6×10−4N

A magnetic pole of pole strength 9.2 A m. is placed in a field of induction 50x10 $^{- 6}$ Tesla. The force experienced by the pole is :

The correct option is C 4.6 $\times$ 10 $^{- 4}$ N
$m = 9.2 A m$
$B = 50 \times 10^{- 6} T$
$F = B \times m$
$F = 9.2 \times 50 \times 10^{- 6}$
$= 4.6 \times 10^{- 4} N$