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Question

A magnetic wire of dipole moment 4πAm2 is bent in the form of a semi-circle. What is the new magnetic moment is?


A

πAm2

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B

2πAm2

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C

8Am2

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D

4πAm2

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Solution

The correct option is C

8Am2


Step 1: Given Data

The dipole moment of wire is M=4πAm2.

r is the radius of the semicircle.

Step 2: Formula Used

  1. M=mL, where m is the magnitude of charge and L is the distance between positive and negative charges.
  2. Distance between poles is L=πrr=Lπ.

Step 3: Solution

Now as the wire is in semicircle, the new distance between the poles is L'=2r=2Lπ

And, the new dipole moment is M'=mL'.

Substitute the values of M and L in the equation M=mL:

4πAm2=mLm=4πAm2L

Substitute the values of m and L' in M'.

M'=4πAm2L×2Lπ=8Am2

Hence, the dipole moment is 8Am2.


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