A magnetised wire of magnetic moment $M$ and length $l$ is bent in the form of a semicircle of radius $r$ . The new magnetic moment is :

\frac{M}{π}

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\frac{2 M r}{l}

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\frac{M}{2 π}

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\frac{M}{4 π}

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Solution

The correct option is A $\frac{2 M r}{l}$
$L_{1} = L$
$L_{2} = 2 r$

$\frac{μ_{1}}{L_{1}} = \frac{μ_{2}}{L_{2}}$

$\frac{M}{L} = \frac{μ_{2}}{2 r}$

$μ_{2} = \frac{2 r M}{L}$

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A magnetised wire of magnetic moment $M$ and length $L$ is bent in the form of a semicircle of radius $r$ . Then its magnetic moment is:

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