A magnetised wire of magnetic moment $M$ is bent into an arc of a circle that subtends an angle of $60^{o}$ at the centre. The equivalent magnetic moment is

\frac{M}{π}

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\frac{2 M}{π}

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\frac{3 M}{π}

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\frac{4 M}{π}

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Solution

The correct option is C $\frac{3 M}{π}$
$r a d i u s = r = \frac{L}{π / 3}$
New magnetic length $= r = 3 L / π$
Magnetic Moment=Magnetic Length x Pole Strength
$∴ M_{n e w} = \frac{3 M}{π}$

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A magnetised wire of magnetic moment M is bent into an arc of a circle that subtends an angle of 60o at the centre. The equivalent magnetic moment is

The correct option is C 3Mπradius=r=Lπ/3New magnetic length =r=3L/πMagnetic Moment=Magnetic Length x Pole Strength∴Mnew=3Mπ

A magnetised wire of magnetic moment $M$ is bent into an arc of a circle that subtends an angle of $60^{o}$ at the centre. The equivalent magnetic moment is

The correct option is C $\frac{3 M}{π}$
$r a d i u s = r = \frac{L}{π / 3}$
New magnetic length $= r = 3 L / π$
Magnetic Moment=Magnetic Length x Pole Strength
$∴ M_{n e w} = \frac{3 M}{π}$