A magnetising field of 1500A m−1 produces flux of 2.4×10−5 weber in a iron bar of the cross-sectional area of 0.5cm2. The permeability of the iron bar is?
A
245
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B
250
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C
252
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D
255
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Solution
The correct option is D255 Here, H=1500A m−1,ϕ=2.4×10−5 weber A=0.5cm2=0.5×10−4m2 ∴B=ϕA=2.4×10−50.5×10−4=4.8×10−1T and μ=BH=4.8×10−11500=3.2×10−4 So relative permeability μr=μμo=3.2×10−44π×10−7=0.255×103=255.