The correct option is A 1/8
When a human male is heterozygous for autosomal gene A and B and also a hemizygous for haemophilic gene h then his genotype will be AaBbX h Y as haemophilia is a X-linked recessive disorder. The gametes produced from this genotype will be abX h , abY, ABX h , ABY, AbX h , AbY,aBX h, and aBY. So, the total number of sperm carries abh is 1 out of 8 gametes i.e., 1/8 or 12.5%. Thus, the correct answer is option A.