Question

A male rabbit of genotype AABBDDEE is crossed with a female rabbit of genotype aabbddee to produce F${}_1$ hybrid offspring. How many genetically different gametes can be produced by this F${}_1$ hybrid?

• A. 4
• B. 8
• C. 16
• D. 32

Answer 1

The correct option is C 16

The cross can be understood as shown in the figure.

The different type of gametes possible can be calculated by 2${}^n$ (where n is the number of heterozygous genes).

The genotype of F${}_1$ hybrid is AaBbDdEe. The number of heterozygous genes are 4. So, number of different types of gametes possible are: 2${}^4$ = 16

So, the correct answer is C.