A man 2 m tall, standing on top of a 25 m building observes the angle of depression of the top and bottom of the next building to be 30∘ and 60∘ respectively. The height of the next building is:
The diagram can be visualised as shown in the figure.
Let the height of the next building be h.
In ΔADE,
tan 30∘=27−hDE
1√3=27−hDE ------- I
In ΔABC, tan 60∘=27BC
√3=27BC ------- II
We know that, DE = BC and also by dividing II by I , we get,
3=2727−h
3×(27−h)=27
h=18m