CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Velocity

A man A start...

Question

A man A starts moving east with velocity 6 m/s, another man B starts moving north 30' east with velocity 6m/s. Find velocity of B w. r. t to A

Open in App

Solution

Velocity of Man A= 6i
Velocity of Man B = 6Sin30i + 6Cos30j

Relative velocity = 6i - 6Sin30i - 6Cos30j
= 6i - 3i - 3√3j
= 3i - 3√3j

Magnitude of relative velocity = sqrt(3^2 + (3√3)^2)
= 6 m/s
So velocity of B w.r.t to A is 6m/s.

Hope this helps :)

Suggest Corrections

thumbs-up

9

Similar questions

Q. A man 'A' moves in the north direction with a speed 10 m/s and man 'B' moves in

30^{0}

North of East with 10 m/s. Find the relative velocity of B w.r.t. A.

Q. Ram moves in east direction at a speed of

6 m / s

and Shyam moves

30^{o}

east of north at a speed of

6 m / s

. The magnitude of their relative velocity is

Q. A body of mass

2 k g

is moving with velocity

10 m / s

towards east. Another body of same mass and same velocity moving towards north collides with former and coalsces and moves towards north-east. Its velocity is

Q. A horizontal wind is blowing with a velocity

v

towards north-east. A man starts running towards north with acceleration

a

. The time after which man will feel the wind blowing towards east is

A

starts from rest and moves with an acceleration of

5 {m/s}^{2}

due East while another particle

B

moves with a constant velocity of

5 m/s

due North from the same position. Then the magnitude of relative position of

A

B

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Velocity

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon