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Question


A man and a plank have mass 20kg each. Friction coefficient between man and plank, as well as plank and ground is 0.1. If force applied by man on string is 15N horizontally, then value of net force on man is (g=10m/s2).

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A
15 N
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B
30 N
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C
20 N
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D
Zero
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Solution

The correct option is B Zero
fr1max=fravailableatmansfeet=0.1(20)(10)=20N
fr2=fravailableatground=0.1(40)(10)=40N
As force applied by man on string is 15 N which is less than the maximum friction forces for both the surfaces. Hence Box will not move.
So net friction on man is =1515=0 N
264748_76792_ans.jpg

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