A man and a woman $63$ miles apart from each other, start travelling towards each other at the same time. If the man covers $4$ miles per hour and the women $3$ miles per hour. How far will the woman have travelled when they met?

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Solution

$D i s t a n c e b e t w e e n t h e m a n a n d w o m a n = 63 m i l e s L e t t h e t i m e a f t e r t h e y m e e t b e x, G i v e n, 4 x + 3 x = 63, x = 9, d i s t a n c e w o m a n h a s t r a v e l l e d = 3 \times 9 = 27 m i l e s$

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A man and a woman 63 miles apart from each other, start travelling towards each other at the same time. If the man covers 4 miles per hour and the women 3 miles per hour. How far will the woman have travelled when they met?

Distancebetweenthemanandwoman=63milesLetthetimeaftertheymeetbex,Given,4x+3x=63,x=9,distancewomanhastravelled=3×9=27miles

A man and a woman $63$ miles apart from each other, start travelling towards each other at the same time. If the man covers $4$ miles per hour and the women $3$ miles per hour. How far will the woman have travelled when they met?

$D i s t a n c e b e t w e e n t h e m a n a n d w o m a n = 63 m i l e s L e t t h e t i m e a f t e r t h e y m e e t b e x, G i v e n, 4 x + 3 x = 63, x = 9, d i s t a n c e w o m a n h a s t r a v e l l e d = 3 \times 9 = 27 m i l e s$