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Question

A man applies a constant force of 5 N on an object of mass 2 kg and displaces it by 5 m. The object was initially at rest. The final velocity of object is

A
10 m/s
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B
5 m/s
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C
25 m/s
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D
15 m/s
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Solution

The correct option is B 5 m/s
Given, force=5 N, mass =2 kg, displacement =5 m and initial velocity(u)=0 m/s as object was initially at rest.

Applying Work - Energy theorem,
Net work done = Change in Kinetic energy.

W=Force×Displacement=12m(v2u2)
5×5=12m(v2u2) as (u=0)
25=12×2×(v2)
v=5 m/s

Hence option B is the correct answer.

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