A man at height of $135 m$ from ground tries to catch the body but he misses. After how much time from now he will be able to catch the body again?

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Solution

$T = \sqrt{\frac{2 H}{g}}$

$= \sqrt{\frac{2 \times 45}{10}} = 3 s e c$

$T = 38 e c + 38 e c$
$= 68 e c$

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A man at height of 135m from ground tries to catch the body but he misses. After how much time from now he will be able to catch the body again?

T=√2Hg =√2×4510=3secT=38ec+38ec =68ec

A man at height of $135 m$ from ground tries to catch the body but he misses. After how much time from now he will be able to catch the body again?

$T = \sqrt{\frac{2 H}{g}}$

$= \sqrt{\frac{2 \times 45}{10}} = 3 s e c$

$T = 38 e c + 38 e c$
$= 68 e c$