A man born in the first half of the nineteenth century was x years old in the year x2. He was born in:
A
1836
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B
1849
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C
1812
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D
1806
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Solution
The correct option is D 1806 We seek an integer whose square is between 1800 and 1850 . There is one, and only one, such integer, namely 1849=432.∴1849−43=1806, the year of birth.
∴ (B) is the correct option.