Question

A man borrows Rs. 8000 at 12% p.a. simple interest and B borrows Rs. 9100 at 10% p.a. simple interest. In how many years will their amounts of debts be equal ?

Answer 1

Let the required time be t years. Then,

$8000+8000\times 12\times t=9100+9100\times 10\times t$

$8000+960t=9100+910t$

$50t=1100$

$t=22$ $years$