Question

A man bought 2 boxes for Rs.1300. He sold one box at a profit of 20% and other box at a loss of 12%. If the selling price of both the boxes is the same, then find the cost price of each box.

Answer 1

Let the C.P. of the first box which was sold at a profit of 20% be Rs.x Then the C.P. of the second box which was sold at a loss of 12% will be Rs.(1300 - x)
Since the first box was sold a profit of 20% its S.P. = $Rs.\frac{120}{100}\times x$
Because the 2nd box was sold at a loss of 12% Hence its S.P. = Rs.$\frac{88}{100}\times (1300-x)$
Since the S.P. of both the boxes are the same We have $\frac{120x}{100}=\frac{88(1300-x)}{100}\Rightarrow 15x-11(1300-x)\Rightarrow 15x+11x=11\times 1300$
$\Rightarrow x=\frac{11\times 1300}{26}=550$