A man bought a certain number of toys for RS 180 ,he kept one for his own use and sold rest of it for one rupee each more than he gave for them , besides getting his own toy for nothing he made a profit of RS 10. Find no of toys.

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Solution

Let the number of toys = x
Cost of each toy = 180/x Rs.
Now no. of toys sold = x-1 and selling price of each = (180/x)+1
He sold the toys for (x-1){(180/x)+1)Rs.
His profit is 10 Rs.
(x-1){(180/x)+1}-180 = 10
solve
x= 20 and -9
rejecting -9
20 toys were bought

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A man bought a certain number of toys for RS 180 ,he kept one for his own use and sold rest of it for one rupee each more than he gave for them , besides getting his own toy for nothing he made a profit of RS 10. Find no of toys.

Let the number of toys = x Cost of each toy = 180/x Rs. Now no. of toys sold = x-1 and selling price of each = (180/x)+1 He sold the toys for (x-1){(180/x)+1)Rs. His profit is 10 Rs. (x-1){(180/x)+1}-180 = 10 solve x= 20 and -9 rejecting -9 20 toys were bought

Let the number of toys = x
Cost of each toy = 180/x Rs.
Now no. of toys sold = x-1 and selling price of each = (180/x)+1
He sold the toys for (x-1){(180/x)+1)Rs.
His profit is 10 Rs.
(x-1){(180/x)+1}-180 = 10
solve
x= 20 and -9
rejecting -9
20 toys were bought